# Line slope calculator 4x-5y=-26

**Straight line given by points A[1; 6] and B[6; 10]**

## Calculation:

**Slope-intercept form of line:**y = 0.8x+5.2

**Canonical form of the line equation:**4x-5y+26 = 0

**Parametric form of the line equation:**

x = 5t+1

y = 4t+6 ; t ∈ R

**Slope:**m = 0.8

**Slope angle of line: φ =**38°39'35″ = 0.6747 rad

**X intercept:**x

_{0}= -6.5

**Y intercept:**y

_{0}= q = 5.2

**Distance line from the origin:**d

_{0}= 4.0605

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; 4)

**Normal vector: n =**(4; -5)

**Midpoint of the segment AB: M =**[3.5; 8]

**Perpendicular Bisector equation:**5x+4y-49.5 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (6; 10) ; |OB| = 11.6619**

**Scalar product OA .OB = 66**

**Angle ∠ AOB = 21°30'5″ = 0.3753 rad**